About
Circular linked lists have either the head or the tail pointing to each other such that the list does not have a beginning nor an end (or rather the two coincide). It is possible to have a singly-linked circular list as well as, more commonly, a doubly circular linked list.
![\begin{tikzpicture}[list/.style={rectangle split, rectangle split parts=3,
draw, rectangle split horizontal}, >=stealth, start chain, square/.style={rectangle, draw}]
% \node[on chain,draw,inner sep=6pt] (X) {\scriptsize\texttt{null}};
\node[list,on chain] (A) {\nodepart{second} $a$};
\node[list,on chain] (B) {\nodepart{second} $b$};
\node[list,on chain] (C) {\nodepart{second} $c$};
%\node[on chain,draw,inner sep=6pt] (D) {\scriptsize\texttt{null}};
\path[*->] let \p1 = (A.three), \p2 = (A.center) in (\x1,\y2) edge [bend left] (B);
\path[*->] let \p1 = (B.three), \p2 = (B.center) in (\x1,\y2) edge [bend left] (C);
%\draw[*->] let \p1 = (C.three), \p2 = (C.center) in (\x1,\y2) -- (D);
\path[*->] let \p1 = (C.one), \p2 = (C.one) in (\x1,\y2) edge [bend left] (B);
\path[*->] let \p1 = (B.one), \p2 = (B.one) in (\x1,\y2) edge [bend left] (A);
\path[*->] let \p1 = (C.three), \p2 = (C.center) in (\x1,\y2) edge [in=100,out=100] (A);
\path[*->] let \p1 = (A.one), \p2 = (A.center) in (\x1,\y2) edge [in=-100,out=-100] (C);
\end{tikzpicture}](/lib/exe/fetch.php?media=wiki:latex:/img12a3ace19301c9b450b34448f378367e.png "LaTeX")